I have a list of clothing items and a variable [gender] that contains value for example “♂️” male. Some items on the list of clothing also contain emojis ♀️ or ♂️ in them, something like “Batman suit♂️”. I’m trying to exclude all items with ♀️ if “gender==♂️” and vice versa. I’ve tried to use clothingTop.selectAll.filter(newlist =>newlist.tags.includes([gender])), ald also match(/♀️/i), I’m not sure how to proceed.

  • VioneT@lemmy.worldMEnglish
    2·
    1 month ago

    I forgot to enclose the value=${this[a]} with quotations, so that is one problem. You can remove the value of the option if you are using the value to access back the list like so:

    $output = [this.selectAll.map(a => a.getName).filter(a => gender.includes('♀️') ? !a.includes('♂️') : !a.includes('♀️')).map(a => `<option>${a}</option>`).join('')]

    So that clothingTop will return the list name e.g. Dress♀️, then using it with [clothingList[clothingGroup][clothingTop]] should return the item below it i.e. evening dress with deep neckline.

    Setting the value to this[a] would have the value of the option set directly to evening dress with deep neckline and not Dress♀️ so [clothingList[clothingGroup][clothingTop]] would not work, but you can access the value directly with clothingTop.

    • Koto@lemmy.worldOPEnglish
      1·
      1 month ago

      Yeah that works, much appreciated! I noticed that the value was different from the name, it was lowerCase and no emoji that’s why I couldn’t call it.