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if the people were aranged in 3d in the shape of a tetrahedron (triangular pyramid) this would work out fine
No
Unless the measurement is from the corner to where the lines cross (peak of the pyramid), but that is not at all clear from how the diagram is drawn.
It’s not a square based pyramid, it’s a triangular based pyramid. Imagine the top right hand one floating up onto the air and moving to hover above the centre of the other three (which move to make an equalateral triangle). The distances work but the layout changes.
You mean a tetrahedron.
I do.
Fools!
…limiting themselves to Euclidean geometry…You beat me to it.
Only one of them is limiting himself to Euclidean geometry. The others are perfectly calm.
“…waving a gun around!?…”
Well you see, space isn’t flat in this very localized area!
Ah, D&D rules
D&D still doesn’t have hexagons?
Pffft, Dnd had the ‘first diagonal 5, second diagonal 10’ rule. It worked well enough, aye?
It doesn’t anymore =(
5e uses diagonal = 5’
Well anything after 3.5e is a watered-down, bastardized version of the game anyway.
Alternating diagonals is in the (2014) DMG as an optional rule at least
Oh good! Octagons are a much better approximation of a circle than squares
4e just used “squares” instead of 5 feet, but it, like 5e, used chebyshev distances.
Pathfinder 2e uses alternating diagonals though.
Looks like a tetrahedron to me.
Just wanted to … nevermind.
Too late is too is too late is …
That implies one person is observing 3 other people from the above (or flying over), which is not exactly trivial.
Exactly! The diagram is simply a schematic.
exactly what I came here to say
Tetrahedrons man, tetrahedrons.
So this makes me wonder if one could force a move into a higher dimension by somehow constraining a set of connected distances in this way.
Sort of like protein folding as a way to bootstrap a dimensional jump.
You might like And He Built a Crooked House by Robert Heinlein - the story of a tesseract-shaped house that folds itself into a real tesseract during an earthquake.
Saddle shaped universe confirmed
This is so good hahaha
calm down, they’re constraints on distance, not distance
Thank you
Explanation:
So, Theres the sentence of Pythagoras. It says that c2 = a2 + b2 when the triangle has a 90° corner
Since a square is just 2 triangles, it applies. That means c (the distance from Person a to Person c) should be √(2×1.902). But that is 2.7m.
These instructions are in 3d.
Even if we would take it from the head of person a to the toe of c, its still a triangle
What? Everytime I meet other people we always arange ourselves in the shape of a simplex of the appropriate dimension. Doesn’t everyone?
So the fifth person to arrive moves to the centre of the tetrahedron and shifts roughly 1.299m into the past or future.
I have a few questions.
- How do you attain time offset?
- Doesn’t that make conversation difficult?
- What even is the fifth dimension?
- How do you convert a distance in metres into a distance in time? You would surely then have a universal m/s? Oh, wait, there is a universal speed, it’s the speed of light, which means 1.299m is equivalent to about 4.3 billionths of a second, which is considerably less impressive for question 1 and just not at all problematic for question 2.
- If you’re using very fast motion for your time offset, doesn’t that make conversation even more difficult? How fast would you need to be going to dilate time for a few billionths of a second? Doesn’t Heisenberg uncertainty start to have an impact here? How can you be sure you got it right?
- So, the diagram doesn’t represent it well, but the 1.5m is a minimum. So, I just delay myself by half a heartbeat which is well over 4.3^e-9s.
Yes, but if they’re just minimums, there’s no need for even using the third dimension, let alone the fourth.
Oh, I may have violated distancing protocols then. My personal delay device doesn’t have sub-microsecond accuracy. Should I will have gotten a test for time-invariant COVID ?
I won’t tell if you won’t tell.
If you have to ask, you wouldn’t understand.
If I understood, I wouldn’t have to ask.
Middle one should be 2,12m. 😤
Or the other 4 should be 1,06m if the middle one is correct.
It clearly says 1.5m
ikr? It’s like some people don’t even recognize a tetrahedron
Funnily enough, this is valid under Chebyshev metric, same that kings in chess follow.